0=10p^2-17

Solution for 0=10p^2-17 equation:

0=10p^2-17

We move all terms to the left:

0-(10p^2-17)=0

We add all the numbers together, and all the variables

-(10p^2-17)=0

We get rid of parentheses

-10p^2+17=0

a = -10; b = 0; c = +17;
Δ = b2-4ac
Δ = 02-4·(-10)·17
Δ = 680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{680}=\sqrt{4*170}=\sqrt{4}*\sqrt{170}=2\sqrt{170}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{170}}{2*-10}=\frac{0-2\sqrt{170}}{-20}
=-\frac{2\sqrt{170}}{-20}
=-\frac{\sqrt{170}}{-10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{170}}{2*-10}=\frac{0+2\sqrt{170}}{-20}
=\frac{2\sqrt{170}}{-20}
=\frac{\sqrt{170}}{-10}
$